Calculus 10th Edition

Published by Brooks Cole
ISBN 10: 1-28505-709-0
ISBN 13: 978-1-28505-709-5

Chapter 2 - Differentiation - 2.4 Exercises: 100

Answer

$g'(x)=2xf'(x^2).$

Work Step by Step

Using the Chain Rule: $u=x^2$; $\dfrac{du}{dx}=2x$ $\dfrac{d}{du}f(u)=f'(u)=f'(x^2)$ $\dfrac{d}{dx}f(x)=\dfrac{d}{du}f(u)\times\dfrac{du}{dx}=2xf'(x^2).$
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