Calculus 10th Edition

Published by Brooks Cole
ISBN 10: 1-28505-709-0
ISBN 13: 978-1-28505-709-5

Chapter 2 - Differentiation - 2.4 Exercises: 9

Answer

$g'(x)=-108(4-9x)^3$

Work Step by Step

$u=4-9x$; $\dfrac{du}{dx}=-9$ $g(u)= 3u^4;\dfrac{d}{du}g(u)=12u^3$ $\dfrac{d}{dx}g(x)=\dfrac{d}{du}g(u)\times\dfrac{du}{dx}=12(4-9x)^3(-9)=-108(4-9x)^3.$
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