## Calculus 10th Edition

Published by Brooks Cole

# Chapter 2 - Differentiation - 2.4 Exercises: 2

#### Answer

$u=(x+1).$ $y=u^{-\frac{1}{2}}=\dfrac{1}{\sqrt{u}}$

#### Work Step by Step

Working from the inside out: Take $x$; add $1$ to it $\leftarrow$ "inner function." Take $(x+1)$; raise it the power of $-\dfrac{1}{2}\leftarrow$ "outer function". $u=(x+1).$ $y=u^{-\frac{1}{2}}=\dfrac{1}{\sqrt{u}}$

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