## Calculus 10th Edition

$u=(x+1).$ $y=u^{-\frac{1}{2}}=\dfrac{1}{\sqrt{u}}$
Working from the inside out: Take $x$; add $1$ to it $\leftarrow$ "inner function." Take $(x+1)$; raise it the power of $-\dfrac{1}{2}\leftarrow$ "outer function". $u=(x+1).$ $y=u^{-\frac{1}{2}}=\dfrac{1}{\sqrt{u}}$