Calculus 10th Edition

Published by Brooks Cole
ISBN 10: 1-28505-709-0
ISBN 13: 978-1-28505-709-5

Chapter 2 - Differentiation - 2.3 Exercises: 132

Answer

True.

Work Step by Step

$f(x)=x^n;$ $f^{(n)}(x)=n!x^{0}$ which is a constant, then $f^{(n+1)}(x)=0.$
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