Calculus 10th Edition

Published by Brooks Cole
ISBN 10: 1-28505-709-0
ISBN 13: 978-1-28505-709-5

Chapter 2 - Differentiation - 2.3 Exercises: 128

Answer

$3\cos{x}-3\cos{x}+\sin{x}-\sin{x}=0$

Work Step by Step

$y'=\dfrac{d}{dx}(3\cos{x}+\sin{x})=-3\sin{x}+\cos{x}.$ $y''=\dfrac{d}{dx}(-3\sin{x}+\cos{x})--3\cos{x}-\sin{x}.$ $-3\cos{x}-\sin{x}+3\cos{x}+\sin{x}=0$
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