Calculus 10th Edition

Published by Brooks Cole
ISBN 10: 1-28505-709-0
ISBN 13: 978-1-28505-709-5

Chapter 2 - Differentiation - 2.3 Exercises: 127

Answer

$2\sin{x}-2\sin{x}+3=3.$

Work Step by Step

$y'=\dfrac{d}{dx}(2\sin{x}+3)=2\cos{x}.$ $y''=\dfrac{d}{dx}(2\cos{x})=-2\sin{x}.$ $-2\sin{x}+2\sin{x}+3=3.$
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