Calculus 10th Edition

Published by Brooks Cole
ISBN 10: 1-28505-709-0
ISBN 13: 978-1-28505-709-5

Chapter 2 - Differentiation - 2.3 Exercises: 51

Answer

$f'(x)=x(2\tan(x)+x\sec^2(x))$.

Work Step by Step

Product Rule $f'(x)=((u(x)(v(x))’=u’(x)v(x)+u(x)v’(x))$ $u(x)=x^2 ;u’(x)=2x $ $v(x)=\tan(x) ;v’(x)=\sec^2(x)$ $f'(x)=(2x)(\tan(x))+(\sec^2(x))(x^2)$ $=x(2\tan(x)+x\sec^2(x))$
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