Calculus 10th Edition

Published by Brooks Cole
ISBN 10: 1-28505-709-0
ISBN 13: 978-1-28505-709-5

Chapter 2 - Differentiation - 2.3 Exercises: 5

Answer

The derivative is $3x^2cos(x)-x^3sin(x)$.

Work Step by Step

Product Rule $f'(x)=((u(x)(v(x))’=u’(x)v(x)+u(x)v’(x))$ $u(x)=x^3 ;u’(x)= 3x^2$ $v(x)= cos(x);v’(x)= -sin(x)$ $f'(x)=(3x^2)(cos(x))+(x^3)(-sin(x))=3x^2cos(x)-x^3sin(x)$
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