Calculus 10th Edition

Published by Brooks Cole
ISBN 10: 1-28505-709-0
ISBN 13: 978-1-28505-709-5

Chapter 2 - Differentiation - 2.2 Exercises: 59

Answer

There are no horizontal tangents.

Work Step by Step

First, find the derivative using the power rule, $((x^n)'=nx^{n-1})$ to get $y'=-\frac{2}{x^3}$ Horizontal tangent$\rightarrow y'=0\rightarrow -\frac{2}{x^3}=0 \rightarrow -2=0$ which is not true hence no solution. Therefore the derivative is never $0$ and hence there are no horizontal tangents.
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