Calculus 10th Edition

Published by Brooks Cole
ISBN 10: 1-28505-709-0
ISBN 13: 978-1-28505-709-5

Chapter 2 - Differentiation - 2.2 Exercises: 47

Answer

The derivative is $3x^2+1$.

Work Step by Step

$y=x(x^2+1)=x^3+x$ $y'=(x^3+x)'=(x^3)'+(x)'=3x^2+1$ using the power rule $((x^n)'=nx^{n-1})$ We first distribute the $x$ into the expression to get $x^3+x$ and then using the power rule we differentiate the individual terms to get the final differentiated expression.
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