## Calculus 10th Edition

The derivative is $3x^2+1$.
$y=x(x^2+1)=x^3+x$ $y'=(x^3+x)'=(x^3)'+(x)'=3x^2+1$ using the power rule $((x^n)'=nx^{n-1})$ We first distribute the $x$ into the expression to get $x^3+x$ and then using the power rule we differentiate the individual terms to get the final differentiated expression.