Calculus 10th Edition

Published by Brooks Cole
ISBN 10: 1-28505-709-0
ISBN 13: 978-1-28505-709-5

Chapter 2 - Differentiation - 2.2 Exercises: 44

Answer

$f'(x)=2+\frac{2}{x^3}$

Work Step by Step

$f(x)=\frac{2x^4}{x^3}-\frac{x}{x^3}=2x-\frac{1}{x^2}$ $f'(x)=(2x)'+(-x^{-2})'=2+(-2)(-1)(x^{-2-1})=2+\frac{2}{x^3}$
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