Calculus 10th Edition

Published by Brooks Cole
ISBN 10: 1-28505-709-0
ISBN 13: 978-1-28505-709-5

Chapter 2 - Differentiation - 2.2 Exercises: 40

Answer

The derivative is $3x^2 -2-9x^{-4}$

Work Step by Step

To find $y'$ just differentiate the individual terms using the power rule $((x^n)' = nx^{n-1})$. The derivative of $x^3$ is $3x^2$. The derivative of$-2x$ is $-2$. The derivative of $3x^{-3}$ is equal to $(3)(-3)(x^{-3-1})$ which simplifies to $-9x^{-4}$;therefore, $y' = 3x^2 -2-9x^{-4}$.
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