## Calculus 10th Edition

The derivative is $3x^2 -2-9x^{-4}$
To find $y'$ just differentiate the individual terms using the power rule $((x^n)' = nx^{n-1})$. The derivative of $x^3$ is $3x^2$. The derivative of$-2x$ is $-2$. The derivative of $3x^{-3}$ is equal to $(3)(-3)(x^{-3-1})$ which simplifies to $-9x^{-4}$;therefore, $y' = 3x^2 -2-9x^{-4}$.