Calculus 10th Edition

$y=3x$ and $y=3x+4$
$f(x)=x^{3}+2$ $f'(x)=Mtangent=3x^{2}$ Parallel: Mtangent=Mline $3x-y-4=0$ $y=3x-4$ $Mline=3$ $3x^{2}=3$ $x^{2}=1$ $x=+-1$ going back to the curve: $f(1)=3, f(-1)=1$ $(1,3) and (-1,1)$ Equations: $y-3=3(x-1)$ $y-3=3x-3$ $y=3x$ $y-1=3(x+1)$ $y-1=3x+3$ $y=3x+4$