## Calculus 10th Edition

$\\y=\frac{1}{4}x+\frac{3}{4}$
$\\f(x)=\sqrt {x-1}$ $\\f(x)={(x-1)}^{1/2}$ $\\f’(x)=\frac{1}{2}(x-1)^{\frac{-1}{2}}$ $\\f’(x)=\frac{1}{2\sqrt {x-1}}$ $\\f’(5)=\frac{1}{2\sqrt {5-1}}$ $\\f’(5)=\frac{1}{4}$ Apply to straight line equation (y-y1)=m(x-x1) $\\y-2=\frac{1}{4}(x-5)$ $\\y-2=\frac{1}{4}x-\frac{5}{4}$ $\\y=\frac{1}{4}x+\frac{3}{4}$