Calculus 10th Edition

Published by Brooks Cole
ISBN 10: 1-28505-709-0
ISBN 13: 978-1-28505-709-5

Chapter 2 - Differentiation - 2.1 Exercises: 25

Answer

(a) $(y-4)=-2(x+1)$

Work Step by Step

(a) Take the derivative of the function $f(x)=x^2+3$: $f'(x)=2x$ Plug the $x$-value of the given point into the derivative to get the slope of the tangent line: $f'(-1)=2(-1)=-2$ Plug the slope $m$ and the given point $(x_{1},y_{1})$ into the point-slope formula $(y-y_{1})=m(x-x_{1})$ $(y-4)=-2(x+1)$ This is the point-slope form.
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