Answer
$=13$
Work Step by Step
Use the formula for the magnitude of a vector in the plane, $||v||=\sqrt {v_{1}^{2}+v_{2}^{2}}$ to find the magnitude.
$||v||=\sqrt {12^{2}+(-5)^{2}}=\sqrt {144+25}=\sqrt {169}= 13.$
Calculus 10th Edition
by Larson, Ron; Edwards, Bruce H.
Published by
Brooks Cole
ISBN 10:
1-28505-709-0
ISBN 13:
978-1-28505-709-5
Chapter 11 - Vectors and the Geometry of Space - 11.1 Exercises - Page 755: 32
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