Calculus 10th Edition

Published by Brooks Cole
ISBN 10: 1-28505-709-0
ISBN 13: 978-1-28505-709-5

Chapter 1 - Limits and Their Properties - Review Exercises: 78

Answer

$\lim\limits_{x\to2^-}\dfrac{1}{\sqrt[3]{x^2-4}}=-\infty.$

Work Step by Step

$\lim\limits_{x\to2^-}\dfrac{1}{\sqrt[3]{x^2-4}}=\dfrac{1}{\sqrt[3]{(2^-)^2-4}}=\dfrac{1}{\sqrt[3]{0^-}}=-\infty.$
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