## Calculus 10th Edition

$\lim\limits_{x\to0^+}(x-\dfrac{1}{x^3})=-\infty.$
$\lim\limits_{x\to0^+}(x-\dfrac{1}{x^3})\to$ $\lim\limits_{x\to0^+}(x)=0^+=0.$ $\lim\limits_{x\to0^+}(\dfrac{-1}{x^3})=\dfrac{-1}{(0^+)^3}=-\infty.$ Using Theorem $1.15:$ $\lim\limits_{x\to0^+}(x-\dfrac{1}{x^3})=-\infty.$