Calculus 10th Edition

Published by Brooks Cole
ISBN 10: 1-28505-709-0
ISBN 13: 978-1-28505-709-5

Chapter 1 - Limits and Their Properties - Review Exercises: 77

Answer

$\lim\limits_{x\to0^+}(x-\dfrac{1}{x^3})=-\infty.$

Work Step by Step

$\lim\limits_{x\to0^+}(x-\dfrac{1}{x^3})\to$ $\lim\limits_{x\to0^+}(x)=0^+=0.$ $\lim\limits_{x\to0^+}(\dfrac{-1}{x^3})=\dfrac{-1}{(0^+)^3}=-\infty.$ Using Theorem $1.15:$ $\lim\limits_{x\to0^+}(x-\dfrac{1}{x^3})=-\infty.$
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