Calculus 10th Edition

Published by Brooks Cole
ISBN 10: 1-28505-709-0
ISBN 13: 978-1-28505-709-5

Chapter 1 - Limits and Their Properties - Review Exercises: 75

Answer

$\lim\limits_{x\to-1^+}\dfrac{x+1}{x^3+1}=\dfrac{1}{3}.$

Work Step by Step

$\lim\limits_{x\to-1^+}\dfrac{x+1}{x^3+1}=\lim\limits_{x\to-1^+}\dfrac{(x+1)}{(x+1)(x^2-x+1)}=\lim\limits_{x\to-1^+}\dfrac{1}{x^2-x+1}$ $=\dfrac{1}{(-1^+)^2-(-1^+)+1}=\dfrac{1}{3}.$
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