Calculus 10th Edition

Published by Brooks Cole
ISBN 10: 1-28505-709-0
ISBN 13: 978-1-28505-709-5

Chapter 1 - Limits and Their Properties - Review Exercises: 73

Answer

$\lim\limits_{x\to1^-}\dfrac{x^2+2x+1}{x-1}=-\infty.$

Work Step by Step

$\lim\limits_{x\to1^-}\dfrac{x^2+2x+1}{x-1}=\dfrac{(1^-)^2+2(1^-)+1}{(1^-)-1}=\dfrac{4}{0^-}=-\infty.$
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