## Calculus 10th Edition

Published by Brooks Cole

# Chapter 1 - Limits and Their Properties - Review Exercises: 51

#### Answer

$f(x)$ has an irremovable (vertical asymptote) discontinuity at $x=5.$

#### Work Step by Step

The only restriction on $f(x)$'s domain is that $x\ne5.$ When $x=5,$ the denominator is $0;$ hence, the function has a vertical asymptote at $x=5.$ This discontinuity is not removable.

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