Calculus 10th Edition

Published by Brooks Cole
ISBN 10: 1-28505-709-0
ISBN 13: 978-1-28505-709-5

Chapter 1 - Limits and Their Properties - Review Exercises: 20

Answer

$\lim\limits_{x\to4}\dfrac{x^2-16}{x-4}=8.$

Work Step by Step

$\lim\limits_{x\to4}\dfrac{x^2-16}{x-4}=\lim\limits_{x\to4}\dfrac{(x-4)(x+4)}{(x-4)}$ $=\lim\limits_{x\to4}(x+4)=4+4=8.$ N.B: Possible typo in book where the variables are not the same; in this solution $x$ was used.
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