# Chapter 1 - Limits and Their Properties - Review Exercises: 19

$\lim\limits_{x\to-2}\dfrac{x+2}{x^2-4}=-\dfrac{1}{4}.$

#### Work Step by Step

$\lim\limits_{x\to-2}\dfrac{x+2}{x^2-4}=\lim\limits_{x\to-2}\dfrac{(x+2)}{(x-2)(x+2)}$ $=\lim\limits_{x\to-2}\dfrac{1}{(x-2)}=\dfrac{1}{-2-2}=-\dfrac{1}{4}.$ N.B: Possible typo in book where the variables are not the same; in this solution $x$ was used.

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