Calculus 10th Edition

Published by Brooks Cole
ISBN 10: 1-28505-709-0
ISBN 13: 978-1-28505-709-5

Chapter 1 - Limits and Their Properties - Review Exercises: 13

Answer

$\lim\limits_{t\to4}\sqrt{t+2}=\sqrt{6}.$

Work Step by Step

Using both Theorem $1.4: \lim\limits_{t\to c}\sqrt[n]{t}=\sqrt[n]{c}$ and Theorem $1.5: \lim\limits_{t\to c}(f(g(t)))=f(\lim\limits_{t\to c}g(t)).$ $\lim\limits_{t\to4}\sqrt{t+2}=\sqrt{4+2}=\sqrt{6}.$
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