Calculus 10th Edition

Published by Brooks Cole
ISBN 10: 1-28505-709-0
ISBN 13: 978-1-28505-709-5

Chapter 1 - Limits and Their Properties - 1.5 Exercises: 8

Answer

$\lim\limits_{x\to4^-}f(x)=-\infty.$ $\lim\limits_{x\to4^+}f(x)=-\infty.$

Work Step by Step

$\lim\limits_{x\to4^-}f(x)=\lim\limits_{x\to4^-}\dfrac{-1}{(x-4)^2}=\dfrac{-1}{(4^--4)^2}=\dfrac{-1}{(0^-)^2}=\dfrac{-1}{0^+}=-\infty.$ $\lim\limits_{x\to4^+}f(x)=\lim\limits_{x\to4^+}\dfrac{-1}{(x-4)^2}=\dfrac{-1}{(4^+-4)^2}=\dfrac{-1}{(0^+)^2}=-\infty.$
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