Calculus 10th Edition

Published by Brooks Cole
ISBN 10: 1-28505-709-0
ISBN 13: 978-1-28505-709-5

Chapter 1 - Limits and Their Properties - 1.5 Exercises: 46

Answer

$\lim\limits_{x\to0^-}\dfrac{x+2}{\cot{x}}=0.$

Work Step by Step

$\lim\limits_{x\to0^-}\dfrac{x+2}{\cot {x}}\to$ $\lim\limits_{x\to0^-}(x+2)=0^-+2=2.$ $\lim\limits_{x\to0^-}\cot{x}=\cot{0^-}=-\infty.$ $\lim\limits_{x\to0^-}\dfrac{x+2}{\cot{x}}=\dfrac{2}{-\infty}=0.$
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