Calculus 10th Edition

Published by Brooks Cole
ISBN 10: 1-28505-709-0
ISBN 13: 978-1-28505-709-5

Chapter 1 - Limits and Their Properties - 1.5 Exercises: 40

Answer

$\lim\limits_{x\to0^+}(6-\dfrac{1}{x^3})=-\infty.$

Work Step by Step

$\lim\limits_{x\to0^+}(6-\dfrac{1}{x^3})\to$ $\lim\limits_{x\to0^+}(6)=6.$ $\lim\limits_{x\to0^+}\dfrac{-1}{x^3}=\dfrac{-1}{(0^+)^3}=\dfrac{-1}{0^+}=-\infty.$ By Theorem $1.15:$ $\lim\limits_{x\to0^+}(6-\dfrac{1}{x^3})=-\infty.$
Update this answer!

You can help us out by revising, improving and updating this answer.

Update this answer

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.