Calculus 10th Edition

Published by Brooks Cole
ISBN 10: 1-28505-709-0
ISBN 13: 978-1-28505-709-5

Chapter 1 - Limits and Their Properties - 1.5 Exercises: 19

Answer

Vertical asymptote at $x=-2$ and at $x=1.$

Work Step by Step

$f(x)=\dfrac{3}{x^2+x-2}=\dfrac{3}{(x+2)(x-1)}$ Vertical asymptotes occur when the denominator alone is $0\to$ $(x+2)(x-1)=0\to x=-2$ or $x=1.$
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