## Calculus 10th Edition

Published by Brooks Cole

# Chapter 1 - Limits and Their Properties - 1.4 Exercises: 82

#### Answer

$f(x)$ is continuous over the interval $(-\infty, 0)$U$(0, \infty).$

#### Work Step by Step

Using Theorem $1.12$ with $f(x)=h(g(x))\to h(x)=\cos{x}$ and $g(x)=\dfrac{1}{x}.$ $g(x)$ is continuous for all values of $x$ such that $x\ne0.$ $h(x)$ is continuous for all values of $x.$ Hence, $f(x)=h(g(x))$ is continuous for all values of $x$ such that $x\ne0\to f(x)$ is continuous over the interval $(-\infty, 0)$U$(0, \infty).$

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