Calculus 10th Edition

Published by Brooks Cole
ISBN 10: 1-28505-709-0
ISBN 13: 978-1-28505-709-5

Chapter 1 - Limits and Their Properties - 1.4 Exercises: 9

Answer

$\lim\limits_{x\to5^+}\dfrac{x-5}{x^2-25}=\dfrac{1}{10}.$

Work Step by Step

$\lim\limits_{x\to5^+}\dfrac{x-5}{x^2-25}=\lim\limits_{x\to5^+}\dfrac{x-5}{(x-5)(x+5)}$ $=\lim\limits_{x\to5^+}\dfrac{1}{x+5}=\dfrac{1}{5+5}=\dfrac{1}{10}.$
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