## Calculus 10th Edition

A vertical asymptote at $x=0.$ This discontinuity is not removable.
The only restriction on the domain is that $x$ cannot be equal to $0.$ $\lim\limits_{x\to0^-}=-\infty$ and $\lim\limits_{x\to0^+}=+\infty$ hence there is a vertical asymptote at $x=0.$ Vertical asymptotes are not removable.