Calculus 10th Edition

Published by Brooks Cole
ISBN 10: 1-28505-709-0
ISBN 13: 978-1-28505-709-5

Chapter 1 - Limits and Their Properties - 1.3 Exercises: 69

Answer

$\lim\limits_{h\to0}\dfrac{(1-\cos{h})^2}{h}=0.$

Work Step by Step

$\lim\limits_{h\to0}\dfrac{(1-\cos{h})^2}{h}=\lim\limits_{h\to0}\dfrac{1-\cos{h}}{h}\times\lim\limits_{h\to0}(1-\cos{h})=1(1-\cos{0})$ $=(0)(0)=0.$
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