Calculus 10th Edition

Published by Brooks Cole
ISBN 10: 1-28505-709-0
ISBN 13: 978-1-28505-709-5

Chapter 1 - Limits and Their Properties - 1.3 Exercises: 47

Answer

$\lim\limits_{x\to 0}\dfrac{x}{x^2-x}=-1.$

Work Step by Step

$\lim\limits_{x\to 0}\dfrac{x}{x^2-x}=\lim\limits_{x\to 0}\dfrac{x}{x(x-1)}=\lim\limits_{x\to 0}\dfrac{1}{x-1}=\dfrac{1}{0-1}=-1.$
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