Calculus 10th Edition

$\lim\limits_{x \to 0}\dfrac{x^{2}+3x}{x}=3$
$\lim\limits_{x \to 0}\dfrac{x^{2}+3x}{x}$ Take out common factor $x$ in the numerator and simplify: $\lim\limits_{x \to 0}\dfrac{x^{2}+3x}{x}=\lim\limits_{x \to 0}\dfrac{x(x+3)}{x}=\lim\limits_{x \to 0}x+3=...$ Apply direct substitution to evaluate the limit: $\lim\limits_{x \to 0}x+3=0+3=3$