Calculus 10th Edition

Published by Brooks Cole
ISBN 10: 1-28505-709-0
ISBN 13: 978-1-28505-709-5

Chapter 1 - Limits and Their Properties - 1.3 Exercises: 33

Answer

$\lim\limits_{x\to\frac{5\pi}{6}}\sin{x}=\dfrac{1}{2}.$

Work Step by Step

Using Theorem $1.6:$ $\lim\limits_{x\to\frac{5\pi}{6}}\sin{x}=\sin{\frac{5\pi}{6}}=\dfrac{1}{2}.$
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