Calculus, 10th Edition (Anton)

Published by Wiley
ISBN 10: 0-47064-772-8
ISBN 13: 978-0-47064-772-1

Chapter 6 - Exponential, Logarithmic, And Inverse Trigonometric Functions - 6.3 Derivatives Of Inverse Functions; Derivatives And Integrals Involving Exponential Functions - Exercises Set 6.3: 74

Answer

$=\int{x^{2}dx}=\frac{1}{3}x^{3}+C$

Work Step by Step

$2ln(x)$ can be written as $ln(x^{2})$ by bringing the constant multiplier into the logarithm. This leaves $e^{ln(x^{2})}$, which equals simply $x^{2}$. This leaves $$\int{x^{2}dx}=\boxed{\frac{1}{3}x^{3}+C}$$
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