Answer
$-2e^{-\frac{x}{2}}+C$
Work Step by Step
Let $u=-\frac{x}{2}$. Then $du=-\frac{1}{2}dx$, so $dx=-2du$.
$\int e^{-x/2}dx$
$=\int e^u*(-2)du$
$=-2e^u+C$
$=-2e^{-\frac{x}{2}}+C$
Calculus, 10th Edition (Anton)
by Anton, Howard
Published by
Wiley
ISBN 10:
0-47064-772-8
ISBN 13:
978-0-47064-772-1
Chapter 6 - Exponential, Logarithmic, And Inverse Trigonometric Functions - 6.3 Derivatives Of Inverse Functions; Derivatives And Integrals Involving Exponential Functions - Exercises Set 6.3 - Page 433: 66
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