Answer
$$\frac{3}{\pi}$$
Work Step by Step
Using the average value equation:
$=\frac{1}{-0+\pi / 3} \int_{0}^{\pi / 3} \tan x \sec x d x=[\sec x]_{0}^{\pi / 3}.\frac{3}{\pi} =\left[-\sec 0+\sec \frac{\pi}{3}\right]\frac{3}{\pi}$
$=[-1+2] \frac{3}{\pi}=\frac{3}{\pi}$