Calculus, 10th Edition (Anton)

Published by Wiley
ISBN 10: 0-47064-772-8
ISBN 13: 978-0-47064-772-1

Chapter 4 - Integration - 4.8 Average Value Of A Function And It's Applications - Exercises Set 4.8 - Page 335: 6

Answer

$$\frac{3}{\pi}$$

Work Step by Step

Using the average value equation: $=\frac{1}{-0+\pi / 3} \int_{0}^{\pi / 3} \tan x \sec x d x=[\sec x]_{0}^{\pi / 3}.\frac{3}{\pi} =\left[-\sec 0+\sec \frac{\pi}{3}\right]\frac{3}{\pi}$ $=[-1+2] \frac{3}{\pi}=\frac{3}{\pi}$
Update this answer!

You can help us out by revising, improving and updating this answer.

Update this answer

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.