Answer
$$\frac{2}{\pi}$$
Work Step by Step
Using the average value equation:
$=\frac{1}{-0+\pi} \int_{0}^{\pi} \sin x d x=[-\cos x]_{0}^{\pi}. \frac{1}{\pi} =\frac{2}{\pi}$
Calculus, 10th Edition (Anton)
by Anton, Howard
Published by
Wiley
ISBN 10:
0-47064-772-8
ISBN 13:
978-0-47064-772-1
Chapter 4 - Integration - 4.8 Average Value Of A Function And It's Applications - Exercises Set 4.8 - Page 335: 5
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