Chapter 4 - Integration - 4.8 Average Value Of A Function And It's Applications - Exercises Set 4.8 - Page 335: 17

True.

True $(g+f)_{\text {ave }}=\frac{1}{-a+b} \int_{a}^{b}(g(x)+f(x)) d x=\frac{1}{-a+b} \int_{a}^{b} g(x) d x+\frac{1}{-a+b} \int_{a}^{b} f(x) d x=$ $g_{\text {ave}}+f_{\text {ave}}$ Thus, the correct answer is $\underline{true}$.