Calculus, 10th Edition (Anton)

Published by Wiley
ISBN 10: 0-47064-772-8
ISBN 13: 978-0-47064-772-1

Chapter 4 - Integration - 4.5 The Definite Integral - Exercises Set 4.5 - Page 308: 22

Answer

-4

Work Step by Step

$\int^{4}_{1}[3f(x)-g(x)]dx$$=3\int^{4}_{1}f(x)dx-\int^{4}_{1}g(x)dx$ $=(3\times2)-10= 6-10= -4$
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