Answer
$-\frac{1}{40(5x^4+2)^2}+C$
Work Step by Step
$\int\frac{x^3}{(5x^4+2)^3}dx$
Let $u=5x^4+2$. Then $du=20x^3dx$, so $x^3dx=\frac{du}{20}$.
$=\int\frac{1}{u^3}*\frac{du}{20}$
$=\frac{1}{20}\int u^{-3}du$
$=\frac{1}{20}(\frac{u^{-2}}{-2}+C)$
$=-\frac{1}{40u^2}+C$
$=-\frac{1}{40(5x^4+2)^2}+C$