Calculus, 10th Edition (Anton)

Published by Wiley
ISBN 10: 0-47064-772-8
ISBN 13: 978-0-47064-772-1

Chapter 4 - Integration - 4.3 Integration By Substitution - Exercises Set 4.3 - Page 286: 1

Answer

a. $(x^2 + 1)^{24}/24 + C$ b. $−(cos^{4}x)/4 + C$

Work Step by Step

a. Considering u=($x^{2}+1$) therefore $du=2x dx$ So by substituting, we get, $\int u^{23}du = u^{24}/24 + C$ b. Considering $u=cosx$ therefore $du=-sinx dx$ So by substituting, we get, $−\int u^3du = −u^4/4 + C$
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