Answer
\[\begin{align}
& \left( \mathbf{a} \right)\text{increasing on the interval }\left[ -\frac{1}{2},\infty \right) \\
& \left( \mathbf{b} \right)\text{decreasing on the interval }\left( -\infty ,-\frac{1}{2} \right]\text{ } \\
& \left( \mathbf{c} \right)\text{concave upward on the interval }\left( -2,1 \right) \\
& \left( \mathbf{d} \right)\text{concave downward on the intervals }\left( -\infty ,-2 \right), \left( 1,+\infty \right) \\
& \left( \mathbf{e} \right)\text{inflection points at }x=-2,\text{ }x=1 \\
\end{align}\]
Work Step by Step
\[\begin{align}
& f\left( x \right)=\sqrt[3]{{{x}^{2}}+x+1} \\
& \text{The domain of the function is }\left( -\infty ,\infty \right) \\
& \text{Calculate the first and second derivatives} \\
& f'\left( x \right)=\frac{d}{dx}\left[ \sqrt[3]{{{x}^{2}}+x+1} \right] \\
& f'\left( x \right)=\frac{1}{3}{{\left( {{x}^{2}}+x+1 \right)}^{-2/3}}\left( 2x+1 \right) \\
& f'\left( x \right)=\frac{2x+1}{3{{\left( {{x}^{2}}+x+1 \right)}^{2/3}}} \\
& \text{Find the critical points, set }f'\left( x \right)=0 \\
& f'\left( x \right)=0 \\
& 2x+1=0 \\
& x=-\frac{1}{2} \\
& \text{Interval analysis }\left( -\infty ,-\frac{1}{2} \right),\text{ }\left( -\frac{1}{2},\infty \right) \\
& f''\left( x \right)=\frac{d}{dx}\left[ \frac{2x+1}{3{{\left( {{x}^{2}}+x+1 \right)}^{2/3}}} \right] \\
& \text{Differentiate using wolfram alplha website} \\
& f''\left( x \right)=-\frac{2\left( {{x}^{2}}+x-2 \right)}{9{{\left( {{x}^{2}}+x+1 \right)}^{5/3}}} \\
& f''\left( x \right)=0 \\
& {{x}^{2}}+x-2=0 \\
& \text{By the quadratic formula} \\
& x=-2,\text{ }x=1 \\
& \text{We obtain the sign analysis shown in the following tables} \\
& \begin{matrix}
\text{Interval} & \left( -\infty ,-\frac{1}{2} \right) & \left( -\frac{1}{2},\infty \right) \\
\text{Test Value} & x=-1 & x=0 \\
\text{Sign of }f'\left( x \right) & - & + \\
\text{Conclusion} & \text{Decreasing} & \text{Increasing} \\
\end{matrix} \\
& and \\
& \begin{matrix}
\text{Interval} & \left( -\infty ,-2 \right) & \left( -2,1 \right) & \left( 1,+\infty \right) \\
\text{Test Value} & -5 & 0 & 5 \\
\text{Sign of }f''\left( x \right) & - & + & - \\
\text{Conclusion} & \text{C}\text{. downward} & \text{C}\text{. upward} & \text{C}\text{. downward} \\
\end{matrix} \\
& \\
& \text{Summary:} \\
& \left( \mathbf{a} \right)\text{ }f\left( x \right)\text{ is increasing on the interval }\left[ -\frac{1}{2},\infty \right) \\
& \left( \mathbf{b} \right)\text{ }f\left( x \right)\text{ is decreasing on the intervals }\left( -\infty ,-\frac{1}{2} \right]\text{ } \\
& \left( \mathbf{c} \right)\text{ }f\left( x \right)\text{ is concave upward on the interval }\left( -2,1 \right)\\
& \left( \mathbf{d} \right)\text{ }f\left( x \right)\text{ is concave downward on the intervals }\left( -\infty ,-2 \right), \left( 1,+\infty \right) \\
& \left( \mathbf{e} \right)\text{ Inflection points at }x=-2,\text{ }x=1 \\
\end{align}\]