Answer
$$\int_1^3\int_{-1}^1(2x-4y)dydx=\boxed{16}$$
Work Step by Step
$\int_1^3\int_{-1}^1(2x-4y)dydx=\int_1^3\left(2xy-2y^2\right)\big\vert_{-1}^1dx=\int_1^3(2x-2-(-2x-2))dx=\int_1^34xdx=2x^2\bigg\vert_1^3=18-2=16$
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