Calculus, 10th Edition (Anton)

Published by Wiley
ISBN 10: 0-47064-772-8
ISBN 13: 978-0-47064-772-1

Chapter 14 - Multiple Integrals - 14.1 Double Integrals - Exercises Set 14.1: 2

Answer

$$\int_1^3\int_{-1}^1(2x-4y)dydx=\boxed{16}$$

Work Step by Step

$\int_1^3\int_{-1}^1(2x-4y)dydx=\int_1^3\left(2xy-2y^2\right)\big\vert_{-1}^1dx=\int_1^3(2x-2-(-2x-2))dx=\int_1^34xdx=2x^2\bigg\vert_1^3=18-2=16$
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