Calculus, 10th Edition (Anton)

Published by Wiley
ISBN 10: 0-47064-772-8
ISBN 13: 978-0-47064-772-1

Chapter 1 - Limits and Continuity - 1.2 Computing Limits - Exercises Set 1.2: 9

Answer

-$\frac{4}{5}$

Work Step by Step

x² + 6x + 5 = (x + 1)(x + 5) and x² - 3x - 4 = (x + 1)(x - 4), then: $\frac{x²+6x+5}{x²-3x-4}$ = $\frac{x+5}{x-4}$. Now we have: $\lim\limits_{x \to -1}\frac{x²+6x+5}{x²-3x-4}$ = $\lim\limits_{x \to -1}\frac{x+5}{x-4}$ = $\frac{-1+5}{-1-4}$ = -$\frac{4}{5}$
Update this answer!

You can help us out by revising, improving and updating this answer.

Update this answer

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.