Calculus, 10th Edition (Anton)

Published by Wiley
ISBN 10: 0-47064-772-8
ISBN 13: 978-0-47064-772-1

Chapter 1 - Limits and Continuity - 1.2 Computing Limits - Exercises Set 1.2 - Page 69: 28

Answer

$\lim\limits_{x \to 3^{-}}\frac{1}{|x-3|}$ = + $\infty$

Work Step by Step

$\lim\limits_{x \to 3^{-}}\frac{1}{|x-3|}$ = $\frac{1}{|3^{-}-3|}$ = $\frac{1}{|0^{-}|}$ = $\frac{1}{0^{+}}$ = +$\infty$
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