Answer
$\lim\limits_{x \to 3^{+}}\frac{x}{x-3}$ = +$\infty$
Work Step by Step
$\lim\limits_{x \to 3^{+}}\frac{x}{x-3}$ = $\frac{3^{+}}{3^{+}-3}$ = $\frac{3}{0^{+}}$ = +$\infty$
Calculus, 10th Edition (Anton)
by Anton, Howard
Published by
Wiley
ISBN 10:
0-47064-772-8
ISBN 13:
978-0-47064-772-1
Chapter 1 - Limits and Continuity - 1.2 Computing Limits - Exercises Set 1.2 - Page 69: 15
Update this answer!
You can help us out by revising, improving and updating this answer.
Update this answerAfter you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.
