Chapter 0 - Before Calculus - 0.2 New Functions From Old - Exercises Set 0.2 - Page 25: 38

$a. f(x) = g(h(x))$ $b. f(x) = g(h(x))$

$a. f(x)=x^2+1 $ $ say, h(x) = x^2$ $and, g(x)=x+1$ $Therefore, f(x) = g(h(x))$ $b. f(x)=1/(x-3) $ $ say, h(x) = x-3$ $and, g(x)=1/x$ $Therefore, f(x) = g(h(x))$ $$\boxed{\text{Please see additional work shown in attached image.}}$$