Elementary Technical Mathematics

Published by Brooks Cole
ISBN 10: 1285199197
ISBN 13: 978-1-28519-919-1

Chapter 9 - Section 9.4 - Applications Involving Pairs of Linear Equations - Exercises - Page 338: 9

Answer

The quantity of $\$6.00/bu$ corn is $2700\;bu$ and the quantity of $\$15.00/bu$ corn is $450\;bu$.

Work Step by Step

Let the quantity of $\$6.00/bu$ corn is $x$ and the quantity of $\$15.00/bu$ corn is $y$. Total quantity is $=3150\;bu$. $\Rightarrow x+y=3150$ ...... (1) Total selling price is $\$22,950$ $\Rightarrow 6x+15y=22,950$ ...... (2) Multiply equation (1) by $-6$. $\Rightarrow -6x-6y=-18,900$ ...... (3) Add equation (2) and (3). $\Rightarrow 6x+15y-6x-6y=22,950-18,900$ Simplify. $\Rightarrow 9y=4050$ Divide both sides by $9$. $\Rightarrow y=\frac{4050}{9}$ Simplify. $\Rightarrow y=450$ Substitute the value of $y$ into equation (1). $\Rightarrow x+450=3150$ Subtract $3150$ form both sides. $\Rightarrow x=3150-450$ Simplify. $\Rightarrow x=2700$ Hence, the quantity of $\$6.00/bu$ corn is $2700\;bu$ and the quantity of $\$15.00/bu$ corn is $450\;bu$.
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